JavaScript Coding Practice

Solve DFS of Graph using JavaScript Language

Solve DFS of Graph using JavaScript to enhance your skills with javascript coding practice , master coding concepts, and prepare for interviews with practical exercises and detailed solutions.

DFS of Graph

Difficulty : Easy

Categories :

  • Graphs

Given a connected undirected graph represented as an adjacency list adj, perform a Depth First Search (DFS) traversal starting from vertex 0. Return a list containing the DFS traversal of the graph.

The traversal should visit neighbors in the same order as they appear in the adjacency list.

Constraints:

  • 1 ≤ adj.size() ≤ 104
  • 1 ≤ adj[i][j] ≤ 104
  • Graph is connected and undirected
  • Start vertex is always 0

Examples:

Input: adj = [[2,3,1], [0], [0,4], [0], [2]]
Output: [0,2,4,3,1]
Explanation: DFS path:
1. Start at 0
2. Visit first neighbor 2, then its neighbor 4
3. Backtrack to 0, visit 3
4. Backtrack to 0, visit 1
Input: adj = [[1,2], [0,2], [0,1,3,4], [2], [2]]
Output: [0,1,2,3,4]
Explanation: Follow adjacency list order for neighbor selection

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